Question
Bond angle in $\mathrm{NH}_3$ is more than in $\mathrm{H}_2 \mathrm{O}$. Justify.
✓
Answer
Both $\mathrm{NH}_3$ and $\mathrm{H}_2 \mathrm{O}$ are $\mathrm{sp}^3$ hybridised but there is only one lone pair present on N in $\mathrm{NH}_3$ and two lone pairs on O of $\mathrm{H}_2 \mathrm{O}$. Since lone pair-lone pair repulsion is greater than lone pair-bond pair and bond pair-bond pair repulsions, two lone pairs on oxygen push the bond pairs more closer than one lone pair on nitrogen. This leads to smaller bond angle in $\mathrm{H}_2 \mathrm{O}$ than in $\mathrm{NH}_3$.
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