MCQ
Bond order of $C_2$ vapour is :
- A$\frac{8-4}{2} = 2$
- ✓$\frac{6-2}{2} = 2$
- C$\frac{8-2}{2} = 3$
- D$\frac{10-2}{2} = 4$
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$STATEMENT-2$: In bromobenzene, the inductive effect of the bromo group is more dominant than the mesomeric effect in directing the incoming electrophile.
$C{H_3}C{H_2}COOH\xrightarrow{{SOC{l_2}}}\,B\,$$ \xrightarrow{{N{H_3}}}\,C\,\xrightarrow[{B{r_2}}]{{KOH}}\,D$
The structure of $D$ would be

$(A)$ $SnCl _2 \cdot 2 H _2 O$ is a reducing agent.
$(B)$ $SnO _2$ reacts with $KOH$ to form $K _2\left[ Sn ( OH )_6\right]$.
$(C)$ A solution of $PbCl _2$ in $HCl$ contains $Pb ^{2+}$ and $Cl ^{-}$ions.
$(D)$ The reaction of $Pb _3 O _4$ with hot dilute nitric acid to give $PbO _2$ is a redoxreaction.