STD 11 - 6.2. Equilibrium - II (icon Equilibrium) — JEE STD 11 Science — Question

The molar mass difference between compounds $Q$ and $R$ is $474 \mathrm{~mol}^{-1}$ and between compounds $P$ and $S$ is $172.5 \mathrm{~g} \mathrm{~mol}^{-1}$.

($1$)The number of heteroatoms present in one molecule of $R$ is. . . . .  .

[Use: Molar mass (in g mol ${ }^{-1}$ ): $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$

Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms]

($2$)The total number of carbon atoms and heteroatoms present in one molecule of $S$. . . . . .

[Use: Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ ]: $\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5$

Atoms other than $\mathrm{C}$ and $\mathrm{H}$ are considered as heteroatoms

Give the answer quetion ($1$) and ($2$)

${E^o}_{\left( {{I_2}/{I^ - }} \right)},{E^ \circ }_{\left( {Br^-/B{r_2}} \right)}$ and ${E^ o }_{\left( {{Fe}/{Fe^{2+} }} \right)}$

are respectively $+ 0.54\  V$, $-1.09\  V$ and $0.44\  V$. On the basis of above data which of the following process is non-spontaneous