MCQ
$B.P.$ of ${H_2}O\,({100\,^o}C)$ and ${H_2}S\,( - {42\,^o}C)$ explained by
- AVander Waal's forces
- BCovalent bond
- ✓Hydrogen bond
- DIonic bond
✓
Answer
Correct option: C.
Hydrogen bond
(c) Boiling point of ${H_2}O$ is more than that of ${H_2}S$ because ${H_2}O$ forms hydrogen bonding while ${H_2}S$ does not.
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