Question
Bring out the following conversion ethane to ethene.

Answer

$\text{CH}_3\text{CH}_3\xrightarrow[-\text{HI}]{\text{I}_2/\text{HNO}_3}\text{CH}_3\text{CH}_2\text{I}\xrightarrow{\text{KOH(alc.)}}\text{CH}_2=\text{CH}_2\\ \ \ _{\text{Ethane}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{Ethyl iodide}} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{Ethene}}$

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