MCQ
Bromination take place at
- ✓$a$
- B$b$
- C$c$
- D$d$
✓
Answer
Correct option: A.
$a$
a
$(a)$ Reaction-proceed through stable free radical.
$(a)$ Reaction-proceed through stable free radical.
$\therefore$ formation of stable $3^o$ free radical at $(a)$
$\therefore$ Bromination of $(a)$ is most favourable.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Equal volumes of three acid solutions of $pH \,3, 4$ and $5$ are mixed in a vessel. .........$ \times 10^{-4} \,M$ will be the $H^+$ ion concentration in the mixture ?
→Which of the following molecules has highest dipole moment?
In the transition of $Zn$ atoms to $Z{n^{ + + }}$ ions there is a decrease in the
→ $1$ molal $K _{4} Fe ( CN )_{6}$ solution has a degree of dissociation of $0.4 .$ Its boiling point is equal to that of another solution which contains $18.1$ weight percent of a non electrolytic solute $A$. The molar mass of $A$ is $.......\, u$. (Round off to the Nearest Integer). [Density of water $\left.=1.0\, g\, cm ^{-3}\right]$
→The odd decomposition of carbon chlorine bond form
The two electrons occupying the same orbital are distinguished by:
Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type $[Pd(C_6H_5)_2(SCN)_2]$ and $[Pd(C_6H_5), (NCS)_2]$ are
→On dilution which of the given quality decreases
Disymmetric object is one which is
The correct match between Item $I$ and Item $II$ is
→| Item $I$ | Item $II$ |
| $A$ Ester test | $P$ Tyr |
| $B$ Carbylamine test | $Q$ Asp |
| $C$ Phthalein dye test | $R$ Ser |
| $S$ Lys |