Polymers — Chemistry STD 12 Science — Question

$(a)$ $\begin{array}{*{20}{c}}
  {C{H_3} - CH - Br} \\ 
  {|\,\,} \\ 
  {\,\,\,\,\,{C_2}{H_5}\,} 
\end{array}$          $(b)$ $\begin{array}{*{20}{c}}
  {\,\,Br\,} \\ 
  {|\,} \\ 
  {C{H_3} - C - C{H_3}} \\ 
  {|\,} \\ 
  {\,\,\,\,\,{C_2}{H_5}} 
\end{array}$          $(c)$ $\begin{array}{*{20}{c}}
  {{C_2}{H_5} - CH - C{H_2}Br} \\ 
  {\,\,|\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {{C_2}{H_5}\,\,} 
\end{array}$

${\left( {C{H_3}} \right)_2}CHN = NCH{\left( {C{H_3}} \right)_2}\left( g \right)\xrightarrow[{{{\text{N}}_2}{\text{(g) + }}{{\text{C}}_6}{{\text{H}}_{14}}{\text{(g)}}}]{{250 - 290{}\,^oC}}$

It is found to be a first order reaction. If initial pressure is $P_o$ and pressure of the mixture at time $t$ is $(P_t)$ then rate constant $K$ would be

${\log _{10}}\,\left[ { - \frac{{d\left[ A \right]}}{{dt}}} \right] = {\log _{10}}\,\left[ {\frac{{d\left[ B \right]}}{{dt}}} \right] + 0.3010$

$‘A’$ and $‘B’$ respectively can be