By how much does 3 x^2-5 x+6 exceed x^3-x^2+4 x-1? - Vidyadip

Question

By how much does $3 x^2-5 x+6 $ exceed $ x^3-x^2+4 x-1?$

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Answer

$=\left(3 x^2-5 x+6\right)-\left(x^3-x^2+4 x-1\right)$
$ =3 x^2-5 x+6-x^3+x^2-4 x+1$
$=-x^3+4 x^2-9 x+7$

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