MCQ
By treating alkylchloride with $aq. \text{KOH}$ produce:
- AAlcohol
- B$\text{KCl}$
- CAlkane
- ✓Both $A$ and $B$
✓
Answer
Correct option: D.
Both $A$ and $B$
In the presence of aqueous $\text{KOH},$ alkyl chloride gives the substitution product as alcohol. The reaction can be written as:
$\ce{RCl + KOH(aq) \rightarrow ROH + KCl}$
$\ce{RCl + KOH(aq) \rightarrow ROH + KCl}$
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