MCQ
By what angle should $M_2$ be rotated, so that the light ray after reflection from both mirrors become horizontal (incident angle at $M_1$ mirror is $40^o$)
- ✓$5^o$ clockwise
- B$85^o$ clockwise
- C$5^o$ anticlockwise
- D$15^o$ anticlockwise
✓
Answer
Correct option: A.
$5^o$ clockwise
a
$180-2(90-\theta)=40^{\circ}$
$180-2(90-\theta)=40^{\circ}$
$2 \theta=40^{\circ} \Rightarrow \theta=20^{\circ}$
$5$ clock wise rotation.
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