MCQ
$C + D$ The product $(C)$ and $(D)$ are


- AAcetone $+$ Ethanal
- ✓Acetone $+$ Ehtanoic acid
- CIsobutanal $+$ Methanal
- DIsobutanoic acid $+$ Methanoic acid

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Given : $K _{ sp } Cu ( OH )_2=1 \times 10^{-20}$
$\operatorname{Take} \frac{2.303 RT }{ F }=0.059 \,V$
The reduction potential at $pH =14$ for the above couple is $(-) x \times 10^{-2}\,V$. The value of $x$ is $........$.



Reason : Phosphorus has lower electronegativity than nitrogen.