MCQ
$C-H$ bond length is greatest in
- A${C_2}{H_2}$
- B${C_2}{H_4}$
- ✓${C_2}{H_6}$
- D${C_2}{H_2}B{r_2}$
We can also understand the bond length with the help of the $s$ character.
Higher the $s$-character lesser is the bond length.
This is because higher $s$ character implies that the electrons that are bonded pairs are closely held together, thus making the bond length small as well as strong.
Hybridisation of $C _2 H _6$ is $sp ^3$
The $s$ character in $C _2 H _6$ (Ethane) is: $\frac{1}{4} \times 100=25 \,\%$ which is the least amongst the other given compounds.
Therefore the $C - H$ bond length of $C _2 H _6$ is the longest.
Hence it is the correct option.
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(Density of water $= 1\,gm/ml$ )
$2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I^-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_{2}(\mathrm{aq})$
$\mathrm{E}_{\text {call }}^{\mathrm{e}}=0.24 \mathrm{V}$ at $298\; \mathrm{K}$. The standard Gibbs energy $\left( {{\Delta _r}{{\rm{G}}^ \ominus }} \right)$ of the cell reaction is:
[Faraday constant $\mathrm{F}=96500 \;\mathrm{C} \mathrm{mol}^{-1} $]
| List-$I$ | List-$II$ | ||
| $A$ | $[Fe(H_2O)_6]^{2+}$ | $P$ | $0$ |
| $B$ | $[Fe(H_2O)_6]^{3+}$ | $Q$ | $1$ |
| $C$ | $[Fe(CN)_6]^{4-}$ | $R$ | $2$ |
| $D$ | $[Fe(CN)_6]^{3-}$ | $S$ | $4$ |
| $E$ | $[Ni(H_2O)_4]^{2+}$ | $T$ | $5$ |
$A$ $||$ $B$ $||$ $C$ $||$ $D$ $||$ $E$