MCQ
${C_2}{H_5}CHO$ and ${(C{H_3})_2}CO$ can be distinguished by testing with
- APhenyl hydrazine
- BHydroxylamine
- ✓Fehling solution
- DSodium bisulphite
✓
Answer
Correct option: C.
Fehling solution
c
(c)${C_2}{H_5}CHO + 2C{u^{ + 2}} + 5O{H^ - } \to \mathop {C{u_2}O}\limits_{{\mathop{\rm Re}\nolimits} d\,\,ppt} + 3{H_2}O$
$ + {C_2}{H_5}CO{O^ - }$
$C{H_3}COC{H_3} + 2C{u^{ + 2}} + 5O{H^ - } \to {\rm{No}}\,\,{\rm{reaction}}$
(c)${C_2}{H_5}CHO + 2C{u^{ + 2}} + 5O{H^ - } \to \mathop {C{u_2}O}\limits_{{\mathop{\rm Re}\nolimits} d\,\,ppt} + 3{H_2}O$
$ + {C_2}{H_5}CO{O^ - }$
$C{H_3}COC{H_3} + 2C{u^{ + 2}} + 5O{H^ - } \to {\rm{No}}\,\,{\rm{reaction}}$
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→$\begin{matrix}
{{H}_{2}}C=CH-C{{H}_{2}}-C{{H}_{2}}-CH-C{{H}_{3}}\xrightarrow[Pyridine]{SOC{{l}_{2}}} \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,| \,\,\,\,\,\,\,\, \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\, \\
\end{matrix}$ $(A)\xrightarrow[({{H}_{2}}O)]{{{O}_{3}}/Zn}\underset{{{C}_{5}}{{H}_{9}}ClO}{\mathop{(B)}}\,\xrightarrow{NaB{{H}_{4}}}(C)$
→{{H}_{2}}C=CH-C{{H}_{2}}-C{{H}_{2}}-CH-C{{H}_{3}}\xrightarrow[Pyridine]{SOC{{l}_{2}}} \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,| \,\,\,\,\,\,\,\, \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH\,\,\,\,\,\, \\
\end{matrix}$ $(A)\xrightarrow[({{H}_{2}}O)]{{{O}_{3}}/Zn}\underset{{{C}_{5}}{{H}_{9}}ClO}{\mathop{(B)}}\,\xrightarrow{NaB{{H}_{4}}}(C)$
Compound $(C)$ is