MCQ
${C_2}{H_5}I$ and $A{g_2}O$ reacts to produce
- A${C_2}{H_6}$
- B${C_2}{H_5} - {C_2}{H_5}$
- ✓${C_2}{H_5} - O - {C_2}{H_5}$
- D${C_2}{H_5} - C{H_3}$
✓
Answer
Correct option: C.
${C_2}{H_5} - O - {C_2}{H_5}$
c
(c) ${C_2}{H_5}I$ and $A{g_2}O$ reacts as below
(c) ${C_2}{H_5}I$ and $A{g_2}O$ reacts as below
$2{C_2}{H_5}I + A{g_2}O \to \mathop {{C_2}{H_5}O{C_2}{H_5}}\limits_{{\text{ether}}} + {I_2}$
Thus, ${C_2}{H_5} - O - {C_2}{H_5}$ is produced.
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