MCQ
${({C_2}{H_5}O)_2}CO\xrightarrow[{{H_3}{O^ + }}]{{C{H_3}MgBr(excess)}}A.$ $A$ (alcohol) can also be obtained by
- A$C{H_3}C{H_2}CHO\xrightarrow[{{H_3}{O^ + }}]{{C{H_3}MgBr(2\,mol)}}$
- B$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}CO{C_2}{H_5}\xrightarrow[{{H_3}{O^ + }}]{{C{H_3}MgBr(2\,mol)}}}
\end{array}$ - C$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}CC{H_3}\xrightarrow[{{H_3}{O^ + }}]{{C{H_3}MgBr(1\,mol)}}}
\end{array}$ - ✓as in $(b)$ and $(c)$
