MCQ
${C_2}{H_5}OH$ can be differentiated from $C{H_3}OH$ by
  • A
    Reaction with $HCl$
  • B
    Reaction with $N{H_3}$
  • By iodoform test
  • D
    By solubility in water

Answer

Correct option: C.
By iodoform test
c
(c) ${{C}_{2}}{{H}_{5}}OH\underset{{{I}_{2}}}{\mathop{\xrightarrow{NaOH}}}\,CH{{I}_{3}}$ yellow ppt.

$C{{H}_{3}}OH\underset{{{I}_{2}}}{\mathop{\xrightarrow{NaOH}}}\,$  No reaction

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