MCQ
$C_3H_6Br_2$ can shows :
- ✓Two gem dibromide
- BTwo vic dibromide
- CTwo tert. dibromo alkane
- DTwo sec. dibromo alkane
$\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{Br}_{2}$ can show two different geminal dibromides.
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$\begin{array}{*{20}{c}}
O \\
{||} \\
{C{H_3} - C - C{H_3}}
\end{array}\mathop {\xrightarrow{{Conc.{H_2}S{O_4}}}}\limits_{Distillation} [X]$
$[X]$ will be :
$B + {H_2}O \to C + HCl$
Compound $(A),\,(B)$ and $(C)$ will be respectively