MCQ
$\mathrm{C}^{4+}$ does not exist but $\mathrm{Pb}^{4+}$ exists although both belong to the same group. This is because
  1. Size of carbon is much smaller than $\ce{Pb}$.
  2. Large amount of energy is needed in case of carbon.
  3. Of inert pair effect.
  4. Nucleus cannot hold such a large number of electrons.
The correct statement $(s)$ is/ are.
  • Only $\ce{I}$
  • B
    $\ce{I}$ and $\ce{II}$
  • C
    Only $\ce{III}$
  • D
    $\ce{II, III}$ and $\ce{IV}$

Answer

Correct option: A.
Only $\ce{I}$

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