C_6 H_5 CONHC H_3 can be converted into C_6 H_5 C H_2 NHC H_3 by - Vidyadip

MCQ

${C_6}{H_5}CONHC{H_3}$ can be converted into ${C_6}{H_5}C{H_2}NHC{H_3}$ by

A
$NaB{H_4}$
B
${H_2} - Pd/C$
C
$LiAl{H_4}$
✓
$Zn - Hg/HCl$

✓

Answer

Correct option: D.

$Zn - Hg/HCl$

d
${C_6}{H_5}CONHC{H_3} \,\mathop {\xrightarrow{{Zn - Hg/}}}\limits_{HCl} \,{C_6}{H_5}C{H_2}NHC{H_3}$

This reaction is known as Clemmenson reduction.

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