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Electrochemistry — Chemistry STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 ScienceChemistryElectrochemistry1 Mark
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Answer

Correct option: C.
$\frac{30}{193} x$
(c) : $t=100 min =100 \times 60 sec =6000 sec$
Charge $=$ current $\times$ time $=5 \times 6000=30000 C$
According to the reaction, $M _{\text {(aq) }}^{2+}+2 e ^{-} \longrightarrow M _{(s)}$
( $\because$ Metal is divalent.)
$2 F$ or $2 \times 96500 C$ is required to deposit 1 mole or $x$ $g$ of $M$.
(Given, atomic mass of metal $=x$ )
$\therefore$ For $30000 C$, the mass of metal deposited
$
=\frac{x \times 30000}{2 \times 96500}=\frac{x \times 300}{2 \times 965}=\frac{30 x}{193}
$

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