Let volume of $\mathrm{NaOH}$ for complete reaction
$=V-$ $lit$
$\mathrm{re}$ Mole $2 \mathrm{V} \quad \mathrm{V}$
$\Rightarrow \quad V=3(4-V)$
$\Rightarrow \quad V=3 \,\mathrm{L}$
Maximum possible heat reieased $=6 \times 14$
$=84 \,\mathrm{Kcal}$
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$NH_4NO_{3(s)} \to N_2O_{(g)} + 2H_2O_{(l)}$ .....$kJ$
Statement-$I$: Since fluorine is more electronegative than nitrogen, the net dipole moment of $\mathrm{NF}_3$ is greater than $\mathrm{NH}_3$.
Statement-$II$: In $\mathrm{NH}_3$, the orbital dipole due to lone pair and the dipole moment of $\mathrm{NH}$ bonds are in opposite direction, but in $\mathrm{NF}_3$ the orbital dipole due to lone pair and dipole moments of $N-F$ bonds are in same direction. In the light of the above statements. Choose the most appropriate from the options given below.
