MCQ
Calculate $T_1$ and $T_2$


- ✓$\frac{{\sqrt 3 }}{2}mg,\frac{{mg}}{2}$
- B$mg,\frac{{\sqrt 3 }}{2}mg$
- C$\frac{{\sqrt 3 }}{2}mg,\frac{{\sqrt 3 }}{2}mg$
- D$\frac{{mg}}{2},\frac{{mg}}{2}$

$\mathrm{T}_{1}=\frac{\sqrt{3}}{2} \mathrm{Mg}$
$\frac{\mathrm{T}_{2}}{\sin 150^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$
$\mathrm{T}_{2}=\frac{\mathrm{Mg}}{2}$
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