MCQ
Calculate $T_1$ and $T_2$
  • $\frac{{\sqrt 3 }}{2}mg,\frac{{mg}}{2}$
  • B
    $mg,\frac{{\sqrt 3 }}{2}mg$
  • C
    $\frac{{\sqrt 3 }}{2}mg,\frac{{\sqrt 3 }}{2}mg$
  • D
    $\frac{{mg}}{2},\frac{{mg}}{2}$

Answer

Correct option: A.
$\frac{{\sqrt 3 }}{2}mg,\frac{{mg}}{2}$
a
$\frac{\mathrm{T}_{1}}{\sin 120^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$

$\mathrm{T}_{1}=\frac{\sqrt{3}}{2} \mathrm{Mg}$

$\frac{\mathrm{T}_{2}}{\sin 150^{\circ}}=\frac{\mathrm{Mg}}{\sin 90^{\circ}}$

$\mathrm{T}_{2}=\frac{\mathrm{Mg}}{2}$

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