Question
Calculate the atomic mass (average) of chlorine using the following data:
 
% Natural Abundance
Molar Mass
${ }^{35} \mathrm{Cl}$
75.77
34.9689
${ }^{37} \mathrm{Cl}$
24.23
36.9659

Answer

The average atomic mass of chlorine
$=\begin{bmatrix}\begin{pmatrix}\text{Fractional abundance}\\\text{ of }\ ^{35}\text{C}1\end{pmatrix}\begin{pmatrix}\text{Molar mass}\\\text{of }\ ^{35}\text{C}1 \end{pmatrix}\\+\begin{pmatrix}\text{Fractional abundance}\\\text{ of }\ ^{35}\text{C}1\end{pmatrix}\begin{pmatrix}\text{Molar mass}\\\text{of }\ ^{35}\text{C}1 \end{pmatrix}\end{bmatrix}$
$=\Big[\Big\{\Big(\frac{75.77}{100}\Big)(34.9689)\Big\}+=\Big[\Big\{\Big(\frac{24.23}{100}\Big)(36.9659)\Big\}\Big]$
$= 26.4959 + 8.9568$
$= 35.4527\text{u}$
$\therefore$ The average atomic mass of chlorine = 35.4527u.

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