Calculate the concentration of OH ^ - ion in an aqueous solution … - Vidyadip

Question

Calculate the concentration of $OH ^{-}$ion in an aqueous solution having pH value 8 .

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Answer

$\begin{array}{l}
pH+pOH=14 \\
\therefore pOH=14-pH=14-8=6
\end{array}$
Now, $\text {pOH} =-\log _{10}\left[ OH ^{-}\right]$
$\begin{array}{l}
\therefore \log _{10}\left[OH^{-}\right]=-pOH \\
\begin{aligned}
\therefore\left[OH^{-}\right] & =\text {Antilog }-pOH \\
& =\text { Antilog }-6.0 \\
& =1 \times 10^{-6} M
\end{aligned}
\end{array}$

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