Question
Calculate the current through the circuit and the potential difference across the diode shown in figure. The drift current for the diode is $20\mu\text{A}.$

Answer


Current in the circuit = Drift current

(Since, the diode is reverse biased $=20\mu\text{A})$

Voltage across the diode $=5-\big(20\times20\times10^{-6}\big)$

$=5-\big(4\times10^{-4}\big)=5\text{V}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Three particles of mass m each are placed at the three corners of an equilateral triangle of side a. Find the work which should be done on this system to increase the sides of the triangle to 2a.
Calculate the electric flux passing through the spheres $S_1$ and $S_2$ shown in the figure. The linear charge density of the wire $A B$ shown in the figure is $\lambda=K x$ where $x=$ distance from the end $A$ of the wire measured along its length.
Image
The angles of dip at two places located on the earth are 0° and 90° respectively. Where are the places located?
You are facing a circular wire carrying an electric current. The current is clockwise as seen by you. Is the field at the centre coming towards you or going away from you?
A wire has a length of 2.0m and a resistance of $5.0\Omega.$ Find the electric field existing inside the wire if it carries a current of 10A.
Explain with example why matter particle acquires electric charge.
A parallel plate capacitor is charged with a potential difference 50 V . Thereafter it is discharged by a resistor for 2 sec , due to which its potential decreases by 10 V . Calculate the portion of energy stored in the capacitor.
A ball is projected from a point on the floor with a speed of 15m/s at an angle of 60° with the horizontal. Will it hit a vertical wall 5m away from the point of projection and perpendicular to the plane of projection without hitting the floor? Will the answer differ if the wall is 22m away?
The equation of refraction at a spherical surface is $\frac{\mu_2}{\text{v}}-\frac{\mu_1}{\text{u}}-=\frac{\mu_2-\mu_1}{\text{R}}.$ Taking $\text{R}=\infty,$ show that this equation leads to the equation $\frac{\text{Real depth}}{\text{Apparent depth}}=\frac{\mu_2}{\mu_1}$ for refraction at a plane surface.
A bulb is made using two filaments. A switch selects whether the filaments are used individually or in parallel. When used with a 15V battery, the bulb can be operated at 5W, 10W or 15W. What should be the resistances of the filaments?