Question
Calculate the distance between $A (5, -3)$ and $B$ on the $y-$axis whose ordinate is $9.$
✓
Answer
We know that any point on $y-$axis has co$-$ordinates of the form $(0, y).$
Ordinate of point $B = 9$
Since, $B$ lies of $y-$axis, so its co$-$ordinates are $(0, 9).$
$\text{AB}=\sqrt{(0-5)^2+(9+3)^2} $
$ =\sqrt{25+144} $
$=\sqrt{169}$
$=13 \text{ units }$
Ordinate of point $B = 9$
Since, $B$ lies of $y-$axis, so its co$-$ordinates are $(0, 9).$
$\text{AB}=\sqrt{(0-5)^2+(9+3)^2} $
$ =\sqrt{25+144} $
$=\sqrt{169}$
$=13 \text{ units }$
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