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Transition and Inner Transition Elements — Chemistry STD 12 — Question

Tamilnadu BoardEnglish MediumSTD 12ChemistryTransition and Inner Transition Elements3 Marks
Question
Calculate the equivalent weight of $KMnO _4$ in
  1. Acidic medium
  2. Basic medium
  3. Neutral medium
✓

Answer

1. Equivalent weight of $KMnO _4$ in acidic medium
$
=\frac{\text { Molecular weight of } KMnO _4 \text { }}{\text { No. of moles of electrons transferred }}
$
2. Equivalent weight of $KMnO _4$ in basic medium
$
=\frac{\text { Molecular weight of } KMnO _4 \text { }}{\text { No. of moles of electrons transferred }}
$
3. Equivalent weight of $KMnO _4$ in neutral medium
$
=\frac{\text { Molecular weight of } KMnO _{4 \text { }}}{\text { No. of moles of electrons transferred }}
$

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