MCQ
Calculate the $\lambda$ associated with an electron moving with the velocity of light.
- A$5 \times 10^{-11}\,m$
- B$2.5 \times 10^{-11}\,m$
- C$5 \times 10^{-12}\,m$
- ✓$2.5 \times 10^{-12}\,m$
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Product in above reaction is
$\Delta {H^o}\, = \, +234.1\,\,kJ$
$C(s)\, + {O_2}(g)\, \to \,\,C{O_2}(g)$
Use these equation and $\Delta H^o$ value to calculate $\Delta H^o$ for this reaction:
$4Fe(s) + 3O_2(g) \to 2Fe_2O_3(s)$
.....$kJ$
