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2. structure of atom — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry2. structure of atom1 Mark
MCQ
Calculate the $\lambda$ of $CO_2$ molecule moving with a velocity $440\, m/s.$
  • A
    $\lambda = 1.03 \times 10^{-11}$
  • B
    $\lambda = 2.06 \times 10^{-10}$
  • C
    $\lambda = 4.12 \times 10^{-11}$
  • ✓
    $\lambda = 2.06 \times 10^{-11}$
✓

Answer

Correct option: D.
$\lambda = 2.06 \times 10^{-11}$
d
The wavelength is calculated from the de-Broglie's equation. $\lambda=\frac{h}{m u}=\frac{6.626 \times 10^{-34}}{\frac{44}{1000 \times 6.023 \times 10^{23}} \times 440}=2.06 \times 10^{-11}$

Thus, the wavelength of $C O_{2}$ is $2.06 \times 10^{-11} \mathrm{m}$

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