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MODEL PAPER 1 — Chemistry STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceChemistryMODEL PAPER 12 Marks
Question
Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
✓

Answer

It is given that:
Volume of water, V= 450 mL = 0.45 L
Temperature, T = (37+273) K = 310 K
Number of moles of the polymer, n = $\frac{1}{185000} mol$
We know that:
Osmotic pressure, $\pi=\frac{n}{V} R T$
$=\frac{1}{185000} mol \times \frac{1}{0.45} \times 8.314 \times 10^3 PaLK ^{-1} mol^{-1} \times 310 K$
= 30.98 Pa
= 31 Pa (approximately)

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