Question
Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving 1.0 g of polymer of molar mass 185,000 in 450 mL of water at 37°C.
$\pi=?, \text{V}=450\text{ mL}=0.450\text{L},$
T = 273 + 37 = 310K R = 0.083 L bar mol-1K-1, M2 = 185,000, W2 = 1.0g $\text{M}_2=\frac{\text{W}_2\text{RT}}{\pi\text{V}}$$185,000=\frac{1.0\times0.083\times310}{\pi\times0.450}$
$\pi=\frac{1.0\times0.083\times310}{185,000\times0.450}$
=0.0003 bar.Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.