Calculate the overall complex dissociation equilibrium constant f… - Vidyadip

Question

Calculate the overall complex dissociation equilibrium constant for the $\ce{Cu(NH3)4}^{2+}$ ion, given that $\beta_4$ for this complex is $2.1 \times 10^{13}$.

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Answer

$\beta_{4} =2.1\times10^{13}$
The overall complex dissociation equilibrium constant is the reciprocal of the overall stability constant, $\beta_{4}$
$\therefore\frac{1}{\beta_{4}}=\frac{1}{2.1\times10^{13}}$
$=4.7\times10^{-14}$

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