Calculate the oxidation number of underlined atoms. Cr2O72- - Vidyadip

Question

Calculate the oxidation number of underlined atoms.
Cr₂O₇^2-

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Answer

$Cr _2 O _7^{2-}$
Oxidation of $O =-2$
$Cr _2 O _7^{2-}$ is an ionic species.
$\therefore$ Sum of the oxidation numbers of all atoms $=-2$
$\therefore 2 \times$ (Oxidation number of $Cr )+7 \times$ (Oxidation number of $O )=-2$
$\therefore 2 \times$ (Oxidation number of $Cr )+7 \times(-2)=-2$
$\therefore 2 \times$ (Oxidation number of $Cr )-14=-2$
$\therefore 2 \times$ (Oxidation number of $Cr )=-2+14$
$\therefore$ Oxidation number of $Cr =+\frac{12}{2}$
$\therefore$ Oxidation number of $Cr$ in $Cr _2 O _7^{2-}=+6$

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