Calculate the oxidation number of underlined atoms. H3PO3

Question

Calculate the oxidation number of underlined atoms.
H₃PO₃

✓

Answer

$H _3 PO _3$
Oxidation number of $O =-2$
Oxidation number of $H =+1$
$H _3 PO _3$ is a neutral molecule.
$\therefore$ Sum of the oxidation numbers of all atoms $=0$
$\therefore 3 \times($ Oxidation number of $H )+$ (Oxidation number of $P )+3 \times($ Oxidation number of $O )$ $=0$
$\therefore 3 \times(+1)+$ (Oxidation number of $P)+3 \times(-2)=0$
$\therefore$ Oxidation number of $P+3-6=0$
Oxidation number of $P$ is $H _3 PO _3=+3$

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Complete the information about the properties of subatomic particles in the following table:

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Neutron	n	0			$1.67493 \times 10^{-27}$	1.00867	1