MCQ
Calculate the $pOH$ of a solution at $25\,^oC$ that contains $1\times10^{-10}\, M$ of hydronium ions, i.e. $H_3O^+$
- A$1$
- B$7$
- ✓$4$
- D$9$
✓
Answer
Correct option: C.
$4$
c
$\left|\mathrm{H}^{+}\right|=10^{-10}$
$\left|\mathrm{H}^{+}\right|=10^{-10}$
so $\left|\mathrm{OH}^{-}\right|=\frac{10^{-14}}{10^{-10}}=10^{-4}$
so $\quad \mathrm{pOH}=4$
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