Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsQuestion Bank [ 2022 ]2 Marks
Question
Calculate the stopping potential when the metal with the work function $0.6\ eV$ is illuminated with the light of $2\ eV.$
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Answer
Given: $\varphi_0=0.6 eV , E =2 eV$
To find: Stopping potential $\left( V _0\right)$
Formula: $V _0=\frac{ E -\phi_0}{ e }$
Calculation:
$ V_0=\frac{2 \times 1.6 \times 10^{-19}-0.6 \times 1.6 \times 10^{-1}}{1.6 \times 10^{-19}}$
$=2-0.6$
$=1.4 V $
The stopping potential is $1.4 V$.
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