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States of Matter — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryStates of Matter2 Marks
Question
Calculate the volume occupied by 8.8 g of $\mathrm{CO}_2$ at $31.1^{\circ} \mathrm{C}$ and 1 bar pressure. $\left(R=0.083\right.$ bar $\left.L K^{-1} \mathrm{~mol}^{-1}\right)$
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Answer

$\text{pV}=\text{nRT}$
$\text{pV}=\frac{\text{m}}{\text{M}}\text{RT}$
Volume occupied by 8.8g of $\mathrm{CO}_2$,
$\text{V}=\frac{\text{mRT}}{\text{pM}}$
$=\frac{8.8\text{g}\times0.083\text{bar L K}^{-1}\text{mol}^{-1}\times304.1\text{K}}{1\text{bar}\times44\text{g mol}^{-1}}$
$\text{V}=5.048\text{L}$

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