MCQ
Calculate the wavelength (in nanometer) associated with a proton moving at $1.0 \times 10^3 ms^{-1}$ (Mass of proton $=$ $1.67 \times 10^{-27} kg$ and $h =6.63 \times 10^{-34} Js$ )
- ✓0.40 nm
- B0.032 nm
- C14.0 nm
- D2.5 nm
✓
Answer
Correct option: A.
0.40 nm
(a) 0.40 nm
$
\begin{aligned}
& \text { Explanation: } \lambda=\frac{h}{m v}=\frac{6.63 \times 10^{-34}}{1.67 \times 10^{-27} \times 1 \times 10^3} \\
& =3.97 \times 10^{-10} m \approx 0.40 nm
\end{aligned}
$
$
\begin{aligned}
& \text { Explanation: } \lambda=\frac{h}{m v}=\frac{6.63 \times 10^{-34}}{1.67 \times 10^{-27} \times 1 \times 10^3} \\
& =3.97 \times 10^{-10} m \approx 0.40 nm
\end{aligned}
$
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