Question
Can the mean of a binomial distribution be less than its variance?

Answer

Let X be a binomial veriate with parameters n and p.
Mean = np varience = npq Mean - variance $= np - npq = np (1 - q) = np.$
$p = np^2$ Mean - variance > 0 Mean > variance
So, mean can never be less than variance.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free