Question
Can the mean of a binomial distribution be less than its variance?

Answer

Let $X$ be a binomial veriate with parameters $n$ and $p$. Mean $=n p$ varience $=n p q$ Mean - variance $=n p-n p q=n p(1$ $-q)=n p . p=n p^2$ Mean - variance > $>0$ Mean > varianceSo, mean can never be less than variance.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free