MCQ
Cannizzaro reaction is not shown by
- A$HCHO$
- B$C_6H_5CHO$
- ✓$CH_3CHO$
- DAll of these
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
|
List-$I$ (Complexion) |
List-$II$ (Spin only magnetic moment in B.M.) |
| $A$ ${\left[\mathrm{Cr}\left(\mathrm{NH}_5\right)_0\right]^{3+}}$ | $I$ $4.90$ |
| $B$ ${\left[\mathrm{NiCl}_4\right]^{2-}}$ | $II$ $3.87$ |
| $C$ ${\left[\mathrm{CoF}_6\right]^{3-}}$ | $III$ $0.0$ |
| $D$ ${\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-}}$ | $IV$ $2.83$ |
Choose the correct answer from the options given below:
$C{l_2} + 2B{r^ - }\left( {aq} \right) \to 2C{l^ - }\left( {aq} \right) + B{r_2}$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with