MCQ
Cannizzaro reaction is not shown by
- A$HCHO$
- B${C_6}{H_5}CHO$
- ✓$C{H_3}CHO$
- DAll of these
✓
Answer
Correct option: C.
$C{H_3}CHO$
c
(c) Cannizzaro’s reaction is shown by aldehydes in which $\alpha$$-H$ atom is absent. $C{H_3}CHO$ contains $3$, $\alpha $$-H$ atoms thus, does not show this reaction.
(c) Cannizzaro’s reaction is shown by aldehydes in which $\alpha$$-H$ atom is absent. $C{H_3}CHO$ contains $3$, $\alpha $$-H$ atoms thus, does not show this reaction.
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In the given reaction $[X]$ will be :
→$(A)\xrightarrow[{\begin{array}{*{20}{c}}
{(2){\kern 1pt} A{g_2}O/{H_2}O} \\
{(3){\kern 1pt} \Delta }
\end{array}}]{{(1){\kern 1pt} \,excess\,{\kern 1pt} C{H_3}I/{K_2}C{O_3}}}(B)$ $\xrightarrow[{(iii){\kern 1pt} \Delta }]{{\begin{array}{*{20}{c}}
{(i){\kern 1pt} excess{\kern 1pt} C{H_3}I/{K_2}C{O_3}} \\
{(ii){\kern 1pt} A{g_2}O}
\end{array}}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - CH = C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \,\,\,\,\\
{{\mkern 1mu} {\mkern 1mu} C{H_3}}
\end{array}$
→{(2){\kern 1pt} A{g_2}O/{H_2}O} \\
{(3){\kern 1pt} \Delta }
\end{array}}]{{(1){\kern 1pt} \,excess\,{\kern 1pt} C{H_3}I/{K_2}C{O_3}}}(B)$ $\xrightarrow[{(iii){\kern 1pt} \Delta }]{{\begin{array}{*{20}{c}}
{(i){\kern 1pt} excess{\kern 1pt} C{H_3}I/{K_2}C{O_3}} \\
{(ii){\kern 1pt} A{g_2}O}
\end{array}}}$ $\begin{array}{*{20}{c}}
{{H_2}C = CH - CH - CH = C{H_2}} \\
{|{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} } \,\,\,\,\\
{{\mkern 1mu} {\mkern 1mu} C{H_3}}
\end{array}$
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LIST $II$ (Uses) |
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| $B$ Carbon tetrachloride | $II$ Insecticide |
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