MCQ
Carbinol is
- A${C_2}{H_5}OH$
- ✓$C{H_3}OH$
- C${(C{H_3})_2}CHOH$
- D$C{H_3}C{H_2}CH(OH)C{H_3}$
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Given $\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 4=0.6021$
$C{H_3} - C{H_2} - Br\xrightarrow{{{\text{alc}}{\text{.KCN}}}}$ $C{H_3}C{H_2}CN$$\xrightarrow{{{\text{HOH}}}}X$
Statement $I$ : The metallic radius of $\mathrm{Na}$ is $1.86 \mathrm{~A}^{\circ}$ and the ionic radius of $\mathrm{Na}^{+}$is lesser than $1.86 \mathrm{~A}^{\circ}$.
Statement $II$ : Ions are always smaller in size than the corresponding elements.
In the light of the above statements, choose the correct answer from the options given below :