MCQ
Carbohydrates are used by body mainly
  • A
    For obtaining vitamins
  • As source of energy
  • C
    For all its developmental needs
  • D
    For building muscles

Answer

Correct option: B.
As source of energy
b
(b) Carbohydrates are rich source of energy.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The major product '$B$' is

$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,C{H_3}}\\
{\,\,\,|\,\,}\\
{C{H_3} - C{H_2} - CH - C - N{H_2}}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,}
\end{array}$ $\xrightarrow[\Delta ]{{B{r_2}/KOH}}\left( A \right)\xrightarrow{\begin{subarray}{l} 
  (1)\,\,C{H_3}I\,{\text{(excess)}} \\ 
  (2)\,AgOH/\Delta \, 
\end{subarray} }$ $(B)$

$2\,gm$ of benzoic acid dissolved in $25\,gm$ of benzene shows a depression in freezing point equal to $1.62\ K$ . Molal depression constant for benzene is $4.9\,K\ kg\ mol^{-1}$ . What is $\%$ degree of association of acid
The major product of the following reaction is 

$Image$

Which of the following reaction does not involve carbocation as an intermediate ?
Expression representing the cell potential $(E\,\,cell)$
How many grams of concentrated nitric acid solution should be used to prepare $250\, mL$ of $2.0\, M\, HNO_3\,\,?$ The concentrated acid is $70\% \,\,HNO_3.$
$75\% $ of a first order reaction is completed in $30$  minutes. What is the time required for $93.75\%$ of the reaction (in minutes)
Which one of the following metals forms interstitial hydride easily ?
A compound of mol. wt. $180$ is acetylated to give a compound of mol. wt. $390$. The number of amino groups in the initial compound is
The final product $(III)$ obtained in the reaction sequence 

$C{{H}_{3}}-C{{H}_{2}}-COOH\xrightarrow{PC{{l}_{3}}}I\xrightarrow{{{C}_{6}}{{H}_{6}}/AlC{{l}_{3}}}II\xrightarrow[\text{base/heat}]{N{{H}_{2}}-N{{H}_{2}}}III$