MCQ
Carbon atoms in the compound ${(CN)_4}{C_2}$ are
- A$sp$ hybridized
- B$s{p^2}$ hybridized
- ✓$sp$ and $s{p^2}$ hybridized
- D$sp$, $s{p^2}$ and $s{p^3}$ hybridized

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$H_2C = CH - CH_2 - I \xrightarrow[CC{{l}_{4}}]{HI(excess)}$