MCQ
Carbon atoms in the compound ${(CN)_4}{C_2}$ are
- A$sp$ hybridized
- B$s{p^2}$ hybridized
- ✓$sp$ and $s{p^2}$ hybridized
- D$sp$, $s{p^2}$ and $s{p^3}$ hybridized

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Given : $N -N =159\,kJ\,mol^{-1};\,\,H-H = 436\,kJ\,mol^{-1}$
$N \equiv N = {\text{ }}941{\text{ }}kJ{\text{ }}mo{l^{ - 1}}{\text{ }};{\text{ }}N-H{\text{ }} = {\text{ }}398{\text{ }}kJ{\text{ }}mo{l^{ - 1}}$ .....$kJ\,mol^{-1}$