MCQ
Carbon has zero oxidation number in
- A$CO$
- B$C{H_4}$
- ✓$C{H_2}C{l_2}$
- D$C{H_3}Cl$
$x + 2 - 2 = 0$; $x = 0\,\,in\,\,C{H_2}C{l_2}$.
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(Given data : Molar mass and the molal freezing point depression constant of benzene are $78 g mol ^{-1}$ and $5.12 K kg mol ^{-1}$, respectively)
(Rounded off to the nearest integer)
(Mass of $Li ^{3+}=8.3$ mass of proton)
${C_6}{H_5}C{H_2}Br\xrightarrow[{(ii){H_3}{O^ + }}]{{(i)Mg.Ether}}X$
Product $X$ is

Reason : Orbital motion contributes magnetic moment.