- A$H_2 /Pt$
- B$LiAlH_4$
- ✓$N_2H_4.KOH/ \Delta$
- D$K_2Cr_2O_7.H_2SO_4$
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Reason : Zinc is a powerful reducing agent than copper.
$(i)$ $0.10\, \mathrm{M} \,\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}$ $(ii)$ $0.10\, \mathrm{M}\, \mathrm{Na}_{2} \mathrm{SO}_{4}$ $(iii)$ $0.10\, \mathrm{M}\, \mathrm{KCl}$ $(iv)$ $0.10 \,\mathrm{M} \,\mathrm{Li}_{3} \mathrm{PO}_{4}$
(nearest integer)
[Given : Molar mass of $\mathrm{AB}_2=200 \mathrm{~g} \mathrm{~mol}^{-1} \cdot \mathrm{K}_{\mathrm{b}}$
(molal boiling point elevation const. of water)
$=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$, boiling point of water $=100^{\circ} \mathrm{C}$;
$\mathrm{AB}_2$ ionises as $\left.\mathrm{AB}_2 \rightarrow \mathrm{A}^{2+}+2 \mathrm{~B}^{-}\right]$

$Ag+ I^- \rightarrow AgI +e^-,$ $E^o = 0.152\, V$
$Ag \rightarrow Ag^+ +e^-,$ $E^o =-0.800\, V$
What is the value of log $K_{sp}$ for $AgI$ ? $(2. 303\, RT/F= 0. 059\, V)$
[Given : Molar mass of $A =93\, g\, mol ^{-1}$. Molal depression constant of water is $1.86\, K \,kg\, mol ^{-1}$ ]