MCQ
Carboxylic acids react with diazomethane to form
- AAmine
- BAlcohol
- ✓Ester
- DAmide
Mechanism as shown
Option $\mathrm{C}$ is correct.
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$(I)$ $1\, M$ glucose $(aq.)$
$(II)$ $1\, M$ sodium chloride $(aq.)$
$(III)$ $1\, M$ acetic acid in benzene
$(IV)$ $1\, M$ ammonium phosphate $(aq.)$

$E^o_{Fe^{3+} /Fe} = -0.036\,V,$ $E^o _{Fe^{2+} /Fe} = -0.439\,V$
The value of standard electrode potential for the change,
$Fe^{3+} (aq) + e^- \rightarrow Fe^{2+} (aq)$ will be ........ $V$.