Question
Carry out the division:$-36y^3 \div 9y^2$
✓
Answer
$-36y^3 \div 9y^2$
$ = \frac{{ - 36{y^3}}}{{9{y^2}}}$
$= -4y$
$ = \frac{{ - 36{y^3}}}{{9{y^2}}}$
$= -4y$
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